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The area of the region bounded by the $y$-axis, $y=\cos x, y=\sin x$, when $0 \leq x \leq \frac{\pi}{4}$, is
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$(\sqrt{2}-1)$ sq. units
$\begin{aligned} & =\left(\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\right)-(0+1) \\ & =\sqrt{2}-1\end{aligned}$
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