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The circuit has two oppositely connect ideal diodes in parallel. What is the current following in the circuit?
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1663 Upvotes
Verified Answer
The correct answer is:
$2.00 \mathrm{~A}$
$2.00 \mathrm{~A}$
$D_1$ is reverse biased therefore it will act like an open circuit.
$$
\mathrm{i}=\frac{12}{6}=2.00 \mathrm{~A}
$$
$$
\mathrm{i}=\frac{12}{6}=2.00 \mathrm{~A}
$$
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