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The correct order of increasing bond angles in the following species is
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Verified Answer
The correct answer is:
$\mathrm{ClO}_2^{-} < \mathrm{Cl}_2 \mathrm{O} < \mathrm{ClO}_2$
Key Idea As the number of lone pairs of electrons increases, bond angle decreases due to repulsion between lp-lp. Moreover, as the electronegativity of central atom decreases, bond angle decreases.
Hence, the order of bond angle is
( $\mathrm{Cl}$ is less electronegative as compared to $\mathrm{O}$.)
Hence, the order of bond angle is
( $\mathrm{Cl}$ is less electronegative as compared to $\mathrm{O}$.)
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