Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The equation of a circle with the origin as the centre and passing through the vertices of an equilateral triangle whose altitude is of length 3 units is
MathematicsCircleJEE Main
Options:
  • A x2+y2=9
  • B x2+y2=16
  • C x2+y2=4
  • D x2+y2=1
Solution:
1823 Upvotes Verified Answer
The correct answer is: x2+y2=4

Circle circumscribes the triangle ABC and has center at 0,0.
AD=3
OA=23×3=2
radius of circle, OA=2
Thus, equation of circle is x2+y2=4

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.