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Question: Answered & Verified by Expert
The equation of the circle passing through the foci of the ellipse x216+y29=1, and having centre at 0,3 is
MathematicsEllipseJEE Main
Options:
  • A x2+y2-6y-5=0
  • B x2+y2-6y+5=0
  • C x2+y2-6y-7=0
  • D x2+y2-6y+7=0
Solution:
2747 Upvotes Verified Answer
The correct answer is: x2+y2-6y-7=0

For x216+y29=1

ae=16-9=7

Foci=±7,0

Radius=7+9=4

Equation of circle=x-02+y-32=42

x2+y2-6y-7=0

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