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The flat face of a plano-convex lens of focel length $10 \mathrm{~cm}$ is silvered. A point source placed $30 \mathrm{~cm}$ in front of the curved surface will produce a :
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The correct answer is:
real image $6 \mathrm{~cm}$ away from the lens

$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$
$\frac{1}{f}=\frac{1}{f m}-\frac{2}{f \mid}$
$\frac{1}{f}=\frac{1}{\infty}-\frac{2}{10}=-\frac{1}{5}$
$f=-5$
$\frac{1}{v}+\frac{1}{-30}=-\frac{1}{5}$
$\frac{1}{v}-\frac{1}{5}+\frac{1}{30}$
$=\frac{-6+1}{30}=\frac{-5}{30}$
$v=-6 \mathrm{~cm}$
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