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The flux linked with a coil at any instant ' $t$ ' is given by
$\phi=10 t^2-50 t+250$
The induced emf at $t=3 \mathrm{~s}$ is
Options:
$\phi=10 t^2-50 t+250$
The induced emf at $t=3 \mathrm{~s}$ is
Solution:
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Verified Answer
The correct answer is:
$-10 \mathrm{~V}$
$-10 \mathrm{~V}$
$e=-\frac{d \phi}{d t}=-(20 t-50)=-10$ volt
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