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Question: Answered & Verified by Expert
The following equilibrium constants are given
N2+3H22NH3;K1
N2+O22NO;K2
H2+12O2H2O;K3
The equilibrium constant for the oxidation of 2 mol of NH3 to give NO is
ChemistryChemical EquilibriumNEET
Options:
  • A K1.K2K3
  • B K2.K33K1
  • C K2.K32K1
  • D K22.K3K1
Solution:
1607 Upvotes Verified Answer
The correct answer is: K2.K33K1
N2+3H22NH3;K1
K1=[NH3]2[N2][H2]3
N2+O22NO;K2
H2+12O2H2O;K3
K2=[NO]2[N2][O2];K3=[H2O][H2][O2]1/2
Now, oxidation of NH3 takes places as below
4NH3+5O24NO+6H2O
or 2NH3+52O22NO+3H2O
K=[NO]2[H2O]3[NH3]2[O2]5/2
K=[NO]2[N2][O2].[N2][O2][NH3]2.[N2][H2]3[N2][H2]3.[H2O]3[H2]3[O2]3/2.[H2]3[O2]3/2[O2]5/2
=[NO]2[N2][O2][N2][H2]3[NH3]2.[H2O]3[H2]3[O2]3/2
=K2.1K1.K33=K33K2K1

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