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The following figure shows a logic gate circuit with inputs A and B and output Y. If the voltage waveforms of A, B and Y are as given, then the logic gate is
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Verified Answer
The correct answer is:
NAND gate
The truth table for the waveform is given by
\begin{array}{|c|c|c|c|}
\cline { 2 - 4 } & A & B & Y \\
\cline { 2 - 4 }t_1-t_2 & 0 & 0 & 1 \\
\cline { 2 - 4 }t_2-t_3 & 0 & 1 & 1 \\
\cline { 2 - 4 }t_3-t_4 & 1 & 0 & 1 \\
\cline { 2 - 4 }t_4-t_5 & 1 & 1 & 0 \\
\cline { 2 - 4 }t_5-t_6 & 0 & 0 & 1 \\
\cline { 2 - 4 } & & &
\end{array}
The expression for the output is $Y=\overline{A \cdot B}$
The truth table of the given logic gate matches with NAND gate.
\begin{array}{|c|c|c|c|}
\cline { 2 - 4 } & A & B & Y \\
\cline { 2 - 4 }t_1-t_2 & 0 & 0 & 1 \\
\cline { 2 - 4 }t_2-t_3 & 0 & 1 & 1 \\
\cline { 2 - 4 }t_3-t_4 & 1 & 0 & 1 \\
\cline { 2 - 4 }t_4-t_5 & 1 & 1 & 0 \\
\cline { 2 - 4 }t_5-t_6 & 0 & 0 & 1 \\
\cline { 2 - 4 } & & &
\end{array}
The expression for the output is $Y=\overline{A \cdot B}$
The truth table of the given logic gate matches with NAND gate.
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