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The following graph shows how $\mathrm{T}_{1 / 2}$ (half-life) of a reactant $\mathrm{R}$ changes with the initial reactant concentration $a_0$.
The order of the reaction will be :
Options:
The order of the reaction will be :
Solution:
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Verified Answer
The correct answer is:
$2$
$t_{1 / 2} \propto \frac{1}{a^{n-1}}$
Hence (C)
Hence (C)
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