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Question: Answered & Verified by Expert
The following reaction descomposes N 2 O 5 2NO 2 + 1 2 O 2 . At a 25 degree centigrade the rate constant of the reaction is 5×10-2sec-1 . The initial pressure of N2O5 is 0.2atm. If total pressure of gaseous mixture becomes 0.35atm, then calculate the time of decomposition of N2O5.
ChemistryChemical KineticsJEE Main
Options:
  • A 238.6 seconds
  • B 138.6 seconds
  • C 69.3 seconds
  • D 89.3 seconds
Solution:
1939 Upvotes Verified Answer
The correct answer is: 138.6 seconds
(i) The decomposition reaction is represented by



Total pressure =p0-x+2x+x2=p0+32x=0.2 atm.
or 3x2=0.35-0.2=0.15
x=0.1 atm
Pressure of N2O5 after t seconds,
P=P0-x=0.2-0.1=0.1 atm
Now applying first order rate law
t= 2.303 k log 10 0.2 0.1
=2.3035×10-3log100.20.1=138.6 seconds

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