The following reaction is performed at 298 K . 2 N O g + O 2 g ⇌ 2 N O 2 g The standard free energy of the formation of N O g is 86 . 6 kJ mol - 1 at 298 K . What is the standard free energy of the formation of N O 2 g at 298 K ? ( K P = 1.6 × 10 12 )

Question

The following reaction is performed at 298 K . 2 N O g + O 2 g ⇌ 2 N O 2 g The standard free energy of the formation of N O g is 86 . 6 kJ mol - 1 at 298 K . What is the standard free energy of the formation of N O 2 g at 298 K ? ( K P = 1.6 × 10 12 ), 0.5 [ 2 × 86,600 - R 298 ln ⁡ ( 1.6 × 10 12 ) ], R 298 ln ⁡ 1.6 × 10 12 -86,600, 86,600 + R 298 ln ⁡ ( 1.6 × 10 12 ), 86,600 - ln ⁡ ( 1.6 × 10 12 ) R ( 298 )

MARKS App · Accepted Answer

Δ G reac ∘ = - 2.303 RT log K P = - RT ln K P = - R 2 9 8 ln 1.6 × 1 0 1 2 Δ G reac ∘ = 2 Δ G f NO 2 ∘ - 2 Δ G f NO ∘ ⇒ - R 298 ln 1.6 × 10 12 = 2 Δ G f NO 2 ∘ - 2 × 86.6 × 1 0 3 ⇒ 2 Δ G f NO 2 ∘ = - R 2 9 8 ln 1.6 × 1 0 1 2 + 2 × 86,600 Δ G f NO 2 ∘ = 86,600 - R 2 9 8 2 ln 1.6 × 1 0 1 2 = 0.5 2 × 86,600 - R 2 9 8 ln 1.6 × 1 0 1 2

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