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The formula of borax is
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Verified Answer
The correct answer is:
$\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O}$
Sodium tetraborate decahydrate is a borax molecular formula is
$$
\mathrm{Na}_2\left[\mathrm{~B}_4 \mathrm{O}_5(\mathrm{OH})_4 \cdot 8 \mathrm{H}_2 \mathrm{O} / \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O}\right.
$$
$\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 5 \mathrm{H}_2 \mathrm{O}$ is borax pentahydrate.
$\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 7 \mathrm{H}_2 \mathrm{O}$ is borax heptahydrate.
$\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 2 \mathrm{H}_2 \mathrm{O}$ is borax dihydrate.
$$
\mathrm{Na}_2\left[\mathrm{~B}_4 \mathrm{O}_5(\mathrm{OH})_4 \cdot 8 \mathrm{H}_2 \mathrm{O} / \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O}\right.
$$
$\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 5 \mathrm{H}_2 \mathrm{O}$ is borax pentahydrate.
$\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 7 \mathrm{H}_2 \mathrm{O}$ is borax heptahydrate.
$\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 2 \mathrm{H}_2 \mathrm{O}$ is borax dihydrate.
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