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The formula of the product formed, when sodium thiosulphate solution is added to silver bromide is
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$\mathrm{Na}_3\left[\mathrm{Ag}\left(\mathrm{S}_2 \mathrm{O}_3\right)_2\right]$
When sodium thiosulphate solution is added to $\mathrm{AgBr}$, then sodium argentothiosulphate is obtained.
$\begin{aligned} & \mathrm{AgBr}+2 \mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3 \longrightarrow \mathrm{Na}_3\left[\mathrm{Ag}\left(\mathrm{S}_2 \mathrm{O}_3\right)_2\right] \\ & \text { (colourless) } \\ & \text { sodium argentothiosulphate } \\ & +\mathrm{NaBr} \\ & \end{aligned}$
$\begin{aligned} & \mathrm{AgBr}+2 \mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3 \longrightarrow \mathrm{Na}_3\left[\mathrm{Ag}\left(\mathrm{S}_2 \mathrm{O}_3\right)_2\right] \\ & \text { (colourless) } \\ & \text { sodium argentothiosulphate } \\ & +\mathrm{NaBr} \\ & \end{aligned}$
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