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Question: Answered & Verified by Expert

The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of 15Ω resistance is connected across BD. Calculate the current through the galvanometer when a potential difference of 10 V is maintained across AC.

PhysicsCurrent ElectricityJEE MainJEE Main 2021 (17 Mar Shift 2)
Options:
  • A 2.44μA
  • B 2.44 mA
  • C 4.87 mA
  • D 4.87μA
Solution:
1029 Upvotes Verified Answer
The correct answer is: 4.87 mA

x-10100+x-y15+x-010=0

53x-20y=30  (1)

y-1060+y-x15+y-05=0

17y-4x=10  (2)

on solving (1) & (2)

x=0.865

y=0.792

ΔV=0.073R=15 Ω

i=4.87 mA

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