Search any question & find its solution
Question:
Answered & Verified by Expert
The four quantum numbers of the outermost orbital of $K$ (atomic no. $=19$ ) are
Options:
Solution:
2474 Upvotes
Verified Answer
The correct answer is:
$n=4, l=0, m=0, s=+\frac{1}{2}$
$K_{19}=1 s^2, 2 s^2 2 p^6, 3 s^2 3 p^6, 4 s^1$
for $4 s^1$ electrons.
$n=4, I=0, m=0$ and $s=+\frac{1}{2}$.
for $4 s^1$ electrons.
$n=4, I=0, m=0$ and $s=+\frac{1}{2}$.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.