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The fraction of total volume occupied by the atoms present in a simple cube is
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The correct answer is:
$\frac{\pi}{6}$
Number of atoms per unit cell $=1$ Atoms touch each other along edges. Hence $r=\frac{a}{2}$
$(\mathrm{r}=$ radius of atom and $\mathrm{a}=$ edge length)
Therefore $\%$ $=\frac{\frac{4}{3} \pi r^{3}}{(2 r)^{3}}=\frac{\pi}{6}$
$(\mathrm{r}=$ radius of atom and $\mathrm{a}=$ edge length)
Therefore $\%$ $=\frac{\frac{4}{3} \pi r^{3}}{(2 r)^{3}}=\frac{\pi}{6}$
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