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Question: Answered & Verified by Expert
The fraction of total volume occupied by the atoms present in a simple cube is
ChemistrySolid StateBITSATBITSAT 2011
Options:
  • A $\frac{\pi}{3 \sqrt{2}}$
  • B $\frac{\pi}{4 \sqrt{2}}$
  • C $\frac{\pi}{4}$
  • D $\frac{\pi}{6}$
Solution:
1862 Upvotes Verified Answer
The correct answer is: $\frac{\pi}{6}$
Number of atoms per unit cell $=1$ Atoms touch each other along edges. Hence $r=\frac{a}{2}$
$(\mathrm{r}=$ radius of atom and $\mathrm{a}=$ edge length)
Therefore $\%$ $=\frac{\frac{4}{3} \pi r^{3}}{(2 r)^{3}}=\frac{\pi}{6}$

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