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The free end of a thread wound on a bobbin is passed round a nail A hammered into the wall. The thread is pulled at a constant velocity. Assuming pure rolling of bobbin, find the velocity $v_0 \mid$ of the centre of the bobbin at the instant when the thread forms an angle a with the vertical.
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$\mid\frac{v \bar{R}}{R \sin \alpha-r}\mid$

When the thread is pulled, the bobbin rolls to the right. Resultant velocity of point $B$ along the thread is $\mid v=v_0 \sin \alpha-\omega r \mid$, where $\mid v_0 \sin \alpha \mid$ is the component of translational velocity along the thread and $\mid \omega r|$ linear velocity due to rotation. As the bobbin rolls without slipping, $\mid v_0=\omega R \mid$. Solving the obtained equations, we get $\mid \left.v_0=\frac{v R}{R \sin \alpha-r} \right\rvert\,$
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