$\begin{aligned} & \text { Given, capacitance, } \mathrm{C}=16 \mu \mathrm{F}=16 \times 10^{-6} \mathrm{~F} \\ & \text { Inductance, } \mathrm{L}=\frac{10}{\pi^2} \mathrm{mH}=\frac{10}{\pi^2} \times 10^{-3} \mathrm{H} \\ & \mathrm{X}_{\mathrm{L}}=\mathrm{X}_{\mathrm{C}} \text { or, } \mathrm{L} \omega=\frac{1}{\mathrm{C} \omega} \\ & \text { or } \mathrm{L}(2 \pi \mathrm{f})=\frac{1}{\mathrm{C}(2 \pi \mathrm{f})} \\ & \therefore \mathrm{f}=\sqrt{\frac{1}{\mathrm{LC} 4 \pi^2}} \text { or, frequency, } \mathrm{f}=\frac{1}{2 \pi} \sqrt{\frac{1}{\mathrm{LC}}} \\ & \therefore \mathrm{f}=\frac{1}{2 \pi} \times \sqrt{\frac{10}{\pi^2} \times 10^{-3} \times 16 \times 10^{-6}}=\frac{1}{2 \pi} \times \frac{\pi \times 10^4}{4} \\ & =\frac{10}{8} \mathrm{kHz}\end{aligned}$
$\therefore \mathrm{f}=1.25 \mathrm{kHz}$