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The function $f(x)=2 x^3-9 x^2+12 x+29$ is monotonically increasing in the interval
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Verified Answer
The correct answer is:
$(-\infty, 1) \cup(2, \infty)$
$f(x)=2 x^3-9 x^2+12 x+29$
$\Rightarrow f^{\prime}(x)=6 x^2-18 x+12=6(x-1)(x-2)$ sign scheme
$\Rightarrow f(x)$ is increasing in the interval
$x \varepsilon(\infty-, 1) \cup(2, \infty)$
$\Rightarrow f^{\prime}(x)=6 x^2-18 x+12=6(x-1)(x-2)$ sign scheme
$\Rightarrow f(x)$ is increasing in the interval
$x \varepsilon(\infty-, 1) \cup(2, \infty)$
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