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The function $f(x)=\log \left(x+\sqrt{x^2+1}\right)$, is
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an odd function
an odd function
$f(x)=\log \left(x+\sqrt{x^2+1}\right)$
$f(-x)=-\log \left(x+\sqrt{x^2+1}\right)$
$f(-x)=-f(x)$, i.e., $f(x)$ is an odd function.
$f(-x)=-\log \left(x+\sqrt{x^2+1}\right)$
$f(-x)=-f(x)$, i.e., $f(x)$ is an odd function.
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