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The function $\mathrm{f}(\mathrm{x})=\sec \left[\log \left(\mathrm{x}+\sqrt{1+\mathrm{x}^2}\right)\right]$ is
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The correct answer is:
even
Hints : $\mathrm{f}(\mathrm{x})=\sec \left(\ell \ln \left(\mathrm{x}+\sqrt{1+\mathrm{x}^2}\right)\right)=\sec ($ odd function $)=$ even function
$\because$ sec is an even function
$\because$ sec is an even function
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