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The function $f(x)=\sin x-k x-c$, where $k$ and $c$ are constants, decreases always when
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The correct answer is:
$k \geq 1$
Let $f(x)=\sin x-k x-c$ where $k$ and $c$ are constants
$f^{\prime}(x)=\cos x-k$ $\therefore f$ decreases if $\cos x \leq k$
Thus, $f(x)=\sin x-k x-c$ decrease always when $k \geq 1$
$f^{\prime}(x)=\cos x-k$ $\therefore f$ decreases if $\cos x \leq k$
Thus, $f(x)=\sin x-k x-c$ decrease always when $k \geq 1$
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