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The general solution of $\tan 3 x=1$ is
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Verified Answer
The correct answer is:
$x=n\left(\frac{\pi}{3}\right)+\frac{\pi}{12}, n \in Z$
We know that $\tan \theta=\tan \alpha$ implies
$\theta=n \pi+\alpha$, where $n \in Z$
Given $\tan 3 x=1$
$\therefore \tan 3 x=\tan \frac{\pi}{4} \Rightarrow 3 x=n \pi+\frac{\pi}{4}$
$\therefore \quad \mathrm{x}=\frac{\mathrm{n} \pi}{3}+\frac{\pi}{12}, \quad \mathrm{n} \in Z$
$\theta=n \pi+\alpha$, where $n \in Z$
Given $\tan 3 x=1$
$\therefore \tan 3 x=\tan \frac{\pi}{4} \Rightarrow 3 x=n \pi+\frac{\pi}{4}$
$\therefore \quad \mathrm{x}=\frac{\mathrm{n} \pi}{3}+\frac{\pi}{12}, \quad \mathrm{n} \in Z$
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