The general solution of the equation $ \tan 2 \theta \cdot \tan \theta=1 $ for $ n \in Z $ is

Question

The general solution of the equation $ \tan 2 \theta \cdot \tan \theta=1 $ for $ n \in Z $ is, $ (2 n+1) \frac{\pi}{4} $, $ (2 n+1) \frac{\pi}{6} $, $ (2 n+1) \frac{\pi}{2} $, $ \frac{1}{1}(2 n+1) \frac{\pi}{3} $

MARKS App · Accepted Answer

Given, tan ⁡ 2 θ = 1 tan ⁡ θ ⇒ tan ⁡ 2 θ = tan ⁡ π 2 - θ ⇒ 2 θ = n π + π 2 - θ ⇒ θ = π 6 ( 2 n + 1 )

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