The Gibbs energy change (in J ) for the given reaction at Cu 2 + = Sn 2 + = 1 M and 298 K is : Cu s + Sn 2 + aq . → Cu 2 + aq . + Sn s ; E Sn 2 + Sn 0 = − 0 .16 V , E Cu 2 + Cu 0 = 0 .34 V , Take F = 96500 C mol − 1

Question

The Gibbs energy change (in J ) for the given reaction at Cu 2 + = Sn 2 + = 1 M and 298 K is : Cu s + Sn 2 + aq . → Cu 2 + aq . + Sn s ; E Sn 2 + Sn 0 = − 0 .16 V , E Cu 2 + Cu 0 = 0 .34 V , Take F = 96500 C mol − 1,

MARKS App · Accepted Answer

E cell 0 = E Sn 2 + / Sn 0 - E Cu 2 + / Cu 0 = - 0 . 16 - 0 . 34 = - 0 . 50 V Δ G 0 = - nFE cell 0 = - 2 × 96500 × ( - 0 . 5 ) = 96500 J = 96 . 5 KJ = 96500 J

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