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Question: Answered & Verified by Expert
The greatest and least value of $\sin x \cos x$ are
MathematicsTrigonometric EquationsJEE Main
Options:
  • A $1,-1$
  • B $\frac{1}{2},-\frac{1}{2}$
  • C $\frac{1}{4},-\frac{1}{4}$
  • D $2,-2$
Solution:
2201 Upvotes Verified Answer
The correct answer is: $\frac{1}{2},-\frac{1}{2}$
Let $f(x)=\sin x \cos x=\frac{1}{2} \sin 2 x$
We know $-1 \leq \sin 2 x \leq 1 \Rightarrow-\frac{1}{2} \leq \frac{1}{2} \sin 2 x \leq \frac{1}{2}$
Thus the greatest and least value of f(x) are $\frac{1}{2}$ and $-\frac{1}{2}$ respectively.

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