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The greatest positive integer which divides $(n+16)$ $(n+17)(n+18)(n+19)$, for all positive integers $n$, is
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Verified Answer
The correct answer is:
$24$
Given, $(n+16)(n+17)(n+18)(n+19)$
As we can observe that these numbers are th product of four consecutive natural numbers.
This number gets divided by $4 !=24$.
As we can observe that these numbers are th product of four consecutive natural numbers.
This number gets divided by $4 !=24$.
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