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The greatest positive integer, which divides
$\mathrm{n}(\mathrm{n}+1)(\mathrm{n}+2)(\mathrm{n}+3)$ for all $\mathrm{n} \in \mathbf{N},$ is
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$\mathrm{n}(\mathrm{n}+1)(\mathrm{n}+2)(\mathrm{n}+3)$ for all $\mathrm{n} \in \mathbf{N},$ is
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The correct answer is:
24
The product of $\mathrm{r}$ consecutive integers is divisible byr! . Thus $n(n+1)(n+2)(n+3)$ is divisible by $4 !=24$
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