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Question: Answered & Verified by Expert
The ground state energy of hydrogen atom is $-13.6 \mathrm{eV}$. The energy needed to ionize hydrogen atom from its second excited state will be
PhysicsAtomic PhysicsNEETNEET 2023 (Manipur)
Options:
  • A $1.51 \mathrm{eV}$
  • B $3.4 \mathrm{eV}$
  • C $13.6 \mathrm{eV}$
  • D $6.8 \mathrm{eV}$
Solution:
2207 Upvotes Verified Answer
The correct answer is: $1.51 \mathrm{eV}$
We know that total energy of electron in hydrogen atom is given by $E_\eta=\frac{-13.6}{n^2}$
Also, total energy of electron in second excited state $=\frac{-13.6}{(3)^2}=-1.51 \mathrm{eV}$
$\Rightarrow$ lonization energy or energy required to ionize hydrogen atom from its second excited state $=1.51 \mathrm{eV}$

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