Search any question & find its solution
Question:
Answered & Verified by Expert
The ground state energy of hydrogen atom is $-13.6 \mathrm{eV}$. The energy needed to ionize hydrogen atom from its second excited state will be
Options:
Solution:
2207 Upvotes
Verified Answer
The correct answer is:
$1.51 \mathrm{eV}$
We know that total energy of electron in hydrogen atom is given by $E_\eta=\frac{-13.6}{n^2}$
Also, total energy of electron in second excited state $=\frac{-13.6}{(3)^2}=-1.51 \mathrm{eV}$
$\Rightarrow$ lonization energy or energy required to ionize hydrogen atom from its second excited state $=1.51 \mathrm{eV}$
Also, total energy of electron in second excited state $=\frac{-13.6}{(3)^2}=-1.51 \mathrm{eV}$
$\Rightarrow$ lonization energy or energy required to ionize hydrogen atom from its second excited state $=1.51 \mathrm{eV}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.