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The $\mathrm{H}_{3} \mathrm{O}^{+}$ion has the following shape
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Verified Answer
The correct answer is:
Pyramidal
$\mathrm{H}_{3} \mathrm{O}^{+}$
total valence $e^{-1}$ count
$\begin{array}{l}
\mathrm{O}+\mathrm{H}+\mathrm{H}+\mathrm{H}-\mathrm{e}^{-1}=8 \\
2,6 \quad 1 \quad 1 \quad 1
\end{array}$
using Lever rule
$2|8| 4 \leadsto$ sp $^{3}$ hybrid $(0)$
$\frac{8}{x}$

total valence $e^{-1}$ count
$\begin{array}{l}
\mathrm{O}+\mathrm{H}+\mathrm{H}+\mathrm{H}-\mathrm{e}^{-1}=8 \\
2,6 \quad 1 \quad 1 \quad 1
\end{array}$
using Lever rule
$2|8| 4 \leadsto$ sp $^{3}$ hybrid $(0)$
$\frac{8}{x}$

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