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Question: Answered & Verified by Expert
The [H+] of a resulting solution that is 0.01 M acetic acid (Ka = 1.8 x 10-5) and 0.01 M in benzoic acid (Ka = 6.3 x 10-5) is
ChemistryIonic EquilibriumNEET
Options:
  • A 9 x 10-4
  • B 81 x 10-4
  • C 9 x 10-5
  • D 2.8 x 10-3
Solution:
1233 Upvotes Verified Answer
The correct answer is: 9 x 10-4
H + = k 1 C 1 + k 2 C 2

(for mixture of two weak acids)

        = 1.8 × 1 0 - 5 × 0.01 + 6.3 × 1 0 - 5 × 0.01

        = 18 × 1 0 - 8 + 6 3 × 1 0 - 8

        = 9 × 1 0 - 4

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