Sometimes, when maximum covalency is obtained, the halides become inert to water. Thus, $\mathrm{S}{\mathrm{F}}_6$ is stable. This is because $\mathrm{S}{\mathrm{F}}_6$ is coordinately saturated and sterically hindered. Thus, $\mathrm{S}{\mathrm{F}}_6$ is inert to water, because of kinetic rather than thermodynamic factor. $\mathrm{C}\mathrm{C}{\mathrm{l}}_4$ cannot undergo hydrolysis as carbon does not have vacant d-orbitals to extend its covalency.
Rest other $\mathrm{P}\mathrm{C}{\mathrm{l}}_5,\mathrm{S}\mathrm{i}\mathrm{C}{\mathrm{l}}_4$ and $\mathrm{B}\mathrm{C}{\mathrm{l}}_3$ can undergo hydrolysis as follows
$\mathrm{P}\mathrm{C}{\mathrm{l}}_5+4{\mathrm{H}}_2\mathrm{O}\to {\mathrm{H}}_3\mathrm{P}{\mathrm{O}}_4+5{\mathrm{H}}^{+}\mathrm{C}{\mathrm{l}}^{-}$
$\mathrm{S}\mathrm{i}\mathrm{C}{\mathrm{l}}_4+4{\mathrm{H}}_2\mathrm{O}\to \mathrm{S}\mathrm{i}(\mathrm{O}\mathrm{H}{)}_4+4{\mathrm{H}}^{+}\mathrm{C}{\mathrm{l}}^{-}$
$\mathrm{B}\mathrm{C}{\mathrm{l}}_3+3{\mathrm{H}}_2\mathrm{O}\to \mathrm{B}(\mathrm{O}\mathrm{H}{)}_3+3{\mathrm{H}}^{+}\mathrm{C}{\mathrm{l}}^{-}$