The heat of formation of N H 3 ( g ) is - 46 k J m o l - 1 . The Δ H (in kJ) of the reaction is 2 N H 3 ( g ) → N 2 ( g ) + 3 H 2 ( g )

Question

The heat of formation of N H 3 ( g ) is - 46 k J m o l - 1 . The Δ H (in kJ) of the reaction is 2 N H 3 ( g ) → N 2 ( g ) + 3 H 2 ( g ), 46, - 46, 92, - 92

MARKS App · Accepted Answer

1 2 N 2 ( g ) + 3 2 H 2 ( g ) → N H 3 ( g ) Δ H r = - 46 k J / m o l 2 N H 3 ( g ) → N 2 ( g ) + 3 H 2 ( g ) Δ H r = - 2 Δ H r = - 2 ( - 46 ) = 92 k J

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