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The heat of neutralisation of a strong acid and a strong alkali is $57.0 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The heat released
when $0.5$ mole of $\mathrm{HNO}_{3}$ solution is mixed with $0.2$ mole of $\mathrm{KOH}$ is
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when $0.5$ mole of $\mathrm{HNO}_{3}$ solution is mixed with $0.2$ mole of $\mathrm{KOH}$ is
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Verified Answer
The correct answer is:
$11.4 \mathrm{~kJ}$
$\because 0.2$ mole will neutralise $0.2$ mole of $\mathrm{HNO}_{3}$.
$$
\begin{aligned}
\therefore \text { Heat evolved } &=57 \times 0.2 \\
&=11.4 \mathrm{~kJ}
\end{aligned}
$$
$$
\begin{aligned}
\therefore \text { Heat evolved } &=57 \times 0.2 \\
&=11.4 \mathrm{~kJ}
\end{aligned}
$$
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