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The height of a waterfall is $50 \mathrm{~m}$. If $g=9.8 \mathrm{~ms}^{-2}$ the difference between the temperature at the top and the bottom of the waterfall is:
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The correct answer is:
$0.117^{\circ} \mathrm{C}$
$\frac{m g h}{J}=m s \Delta t \Rightarrow \Delta t=0.117^{\circ} \mathrm{C}$
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