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The hybridisation of each carbon in the following compound respectively is
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$s p^3, s p^2, s p^3, s p$
In the compound,
The $C$-atoms that is bonded to four different atoms involve four orbitals ( 1 of $s$ and 3 of $p$-orbitals) during
hybridisation. Hence, they have $s p^3$-hybridisation as in cases of (i) and (iii).
The $\mathrm{C}-$ atom bonded to three different atoms involves three orbitals ( 1 of $s$ and 2 of $p$-orbitals). Hence, the $s p^2$-hybridisation in case of (ii).
The $C$-atom bonded to two different atoms involves two orbitals ( 1 of $s$ and 1 of $p$-orbitals). Hence, the $s p$ - hybridisation in case of (iv).
The $C$-atoms that is bonded to four different atoms involve four orbitals ( 1 of $s$ and 3 of $p$-orbitals) during
hybridisation. Hence, they have $s p^3$-hybridisation as in cases of (i) and (iii).
The $\mathrm{C}-$ atom bonded to three different atoms involves three orbitals ( 1 of $s$ and 2 of $p$-orbitals). Hence, the $s p^2$-hybridisation in case of (ii).
The $C$-atom bonded to two different atoms involves two orbitals ( 1 of $s$ and 1 of $p$-orbitals). Hence, the $s p$ - hybridisation in case of (iv).
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