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Question: Answered & Verified by Expert
The incorrect arrangement regarding the properties of the given species is:
Chemistryd and f Block ElementsNEET
Options:
  • A Co 3+ < Fe 3+ < Cr 3+ < Sc 3+ : Stability in aqueous solution
  • B  Sc < Ti < Cr < Mn :Number of oxidation states
  • C V 2+ < Cr 2+ < Mn 2+ < Fe 2+ :Paramagnetic behaviour
  • D ​ Ni 2+ < Co 2+ < Fe 2+ < Mn 2+ : Ionic size
Solution:
1551 Upvotes Verified Answer
The correct answer is: V 2+ < Cr 2+ < Mn 2+ < Fe 2+ :Paramagnetic behaviour
No. of unpaired electrons =n

23 V 2+ →​ Ar  4 s 0  3 d 3 , n= 3

24 Cr 2+ → Ar  4 s 0  3 d 4 , n=4

25 Mn 2+ → Ar  4 s 0  3 d 5 , n=5

26 Fe 2+ → Ar  4 s 0  3 d 6 , n=4

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