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The incorrect statement in respect of chromyl chloride test is
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liberation of chlorine
Chromyl chloride test is used for $\mathrm{Cl}^{-}$ions. Chlorine is not liberated in this test.
$\mathrm{CrO}_{2} \mathrm{Cl}_{2}+4 \mathrm{NaOH} \longrightarrow 2 \mathrm{NaCl}+\mathrm{Na}_{2} \mathrm{CrO}_{4}+2 \mathrm{H}_{2} \mathrm{O}$
$\mathrm{Na}_{2} \mathrm{CrO}_{4}+\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb} \longrightarrow 2 \mathrm{CH}_{3} \mathrm{COONa}+\underset{\text { lead chromate }}{\mathrm{PbCrO}_{4}}$
$\mathrm{CrO}_{2} \mathrm{Cl}_{2}+4 \mathrm{NaOH} \longrightarrow 2 \mathrm{NaCl}+\mathrm{Na}_{2} \mathrm{CrO}_{4}+2 \mathrm{H}_{2} \mathrm{O}$
$\mathrm{Na}_{2} \mathrm{CrO}_{4}+\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb} \longrightarrow 2 \mathrm{CH}_{3} \mathrm{COONa}+\underset{\text { lead chromate }}{\mathrm{PbCrO}_{4}}$
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