In case of polar protic solvents, two factors decide the basic character. The positive inductive effect from alkyl groups which increases basicity.

$3^o>2^o>1^o$ Amine

& the Steric Hindrance. $1^o>2^{ }>3^{\mathrm{o }}$ 

Thus, the resultant basic character is determined by taking the above two factors into account.

So order will be $2^o>1^o>3^o$ if methyl group is present as alkyl group otherwise order will be $2°>3°>1°$.

In aromatic & Aliphatic: Aliphatic Amine are more basic than aromatic because the lone pair of $N$ is involved in delocalization.

So basic character is in the order $2^o>1^o>3^o>\mathrm{A}\mathrm{r}\mathrm{o}\mathrm{m}\mathrm{a}\mathrm{t}\mathrm{i}\mathrm{c}\mathrm{ }\mathrm{A}\mathrm{m}\mathrm{i}\mathrm{n}\mathrm{e}$

So (B) > (A) > (C) > (D)