The increasing order of PH H of 0.1 M solution of the following compounds is

Open MARKS Web Download App

Search any question & find its solution

Question: Answered & Verified by Expert

The increasing order of $\mathrm{PH}^{\mathrm{H}}$ of $0.1 \mathrm{M}$ solution of the following compounds is

ChemistryIonic EquilibriumMHT CETMHT CET 2022 (07 Aug Shift 2)

Options:

A $\mathrm{HCl}<\mathrm{NaCl}<\mathrm{NaCN}<\mathrm{NH}_4 \mathrm{NO}_3$
B $\mathrm{NH}_4 \mathrm{ON}_3<\mathrm{HCl}<\mathrm{NaCl}<\mathrm{NaCH}$
C $\mathrm{BaCN}<\mathrm{HCl} \mathrm{NH}{ }_4 \mathrm{NO}_3<\mathrm{HCl}$
D $\mathrm{HCl}<\mathrm{NH}_4 \mathrm{NO}_3<\mathrm{NaCl}<\mathrm{NaCN}$

Solution:

1813 Upvotes Verified Answer

The correct answer is: $\mathrm{HCl}<\mathrm{NH}_4 \mathrm{NO}_3<\mathrm{NaCl}<\mathrm{NaCN}$

$\mathrm{HCl}$ (SA), $\mathrm{NH}_4 \mathrm{NO}_3$ (SAWB), $\mathrm{NaCl}(\mathrm{SASB}) \mathrm{NaCN}$ (WASB)

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.

Use on iOS or Desktop Download from Google Play