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Question: Answered & Verified by Expert
The integral I=0100πtan-1xdx, (where, . represents the greatest integer function) has the value Kπ+tanp, then the value of K+p is equal to
MathematicsDefinite IntegrationJEE Main
Options:
  • A 101
  • B 99
  • C 100π
  • D 99π
Solution:
1299 Upvotes Verified Answer
The correct answer is: 99
The given integral is I=0tan10dx+tan1100π1dx
as tan-1x1,π2, x>tan1
I=100π-tan1
=100π+tan-1
k=100, p=-1
k+p=99

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