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The intensity of gamma radiation from a given source is I. On passing through $36 \mathrm{~mm}$ of lead, it is reduced to $\frac{I}{8}$. The thickness of lead which will reduce the intensity to $\frac{I}{2}$ will be
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The correct answer is:
$12 \mathrm{~mm}$
$12 \mathrm{~mm}$
Use I $=I_0 e^{-\mu x}$
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