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The intensity of the magnetic induction field at the centre of a single turn circular coil of radius $5 \mathrm{~cm}$ carrying current of $0.9 \mathrm{~A}$.
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Verified Answer
The correct answer is:
$36 \pi \times 10^{-7} \mathrm{~T}$
The intensity of magnetic induction field
$B=\frac{\mu_0 i}{2 r}$
$=\frac{4 \pi \times 10^{-7} \times 0.9}{2 \times 5 \times 10^{-2}}$
$B=36 \pi \times 10^{-7} \mathrm{~T}$
$B=\frac{\mu_0 i}{2 r}$
$=\frac{4 \pi \times 10^{-7} \times 0.9}{2 \times 5 \times 10^{-2}}$
$B=36 \pi \times 10^{-7} \mathrm{~T}$
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