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The intermediate carbocation formed in the reactions of HI, HBr and HCl with propene is the same and the bond energy of HCl, HBr and HI is 430.5 kJ mol–1, 363.7 kJ mol–1and 296.8 kJ mol–1respectively. What will be the order of reactivity of these halogen acids?
ChemistryHydrocarbonsNEET
Options:
  • A Bond dissociation energy is least for HI and maximum for HCl, therefore, order of reactivity will be HI > HBr > HCl.
  • B Bond dissociation energy is maximum for HI and minimum for HCl, therefore, order of reactivity will be HI < HBr < HCl.
  • C Bond dissociation energy is least for HI and maximum for HCl, therefore, order of reactivity will be HI = HBr = HCl.
  • D Bond dissociation energy is least for HCl and maximum for HBr, therefore, order of reactivity will be HCl > HI > HBr.
Solution:
2164 Upvotes Verified Answer
The correct answer is: Bond dissociation energy is least for HI and maximum for HCl, therefore, order of reactivity will be HI > HBr > HCl.
Correct Option is : (A)
Bond dissociation energy is least for HI and maximum for HCl, therefore, order of reactivity will be HI > HBr > HCl.

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