The internal and external diameters of a hollow cylinder are measured with the help of vernier callipers. Their values are 4.23 ± 0.01 cm and 3.87 ± 0.01 cm respectively. The thickness of the wall of the cylinder is

Question

The internal and external diameters of a hollow cylinder are measured with the help of vernier callipers. Their values are 4.23 ± 0.01 cm and 3.87 ± 0.01 cm respectively. The thickness of the wall of the cylinder is, 0.36 ± 0 .02 cm, 0.18 ± 0 .02 cm, 0.36 ± 0 .01 cm, 0.18 ± 0 .01 cm

MARKS App · Accepted Answer

t = D 1 − D 2 2 = 4 .23 − 3 .87 2 = 0 . 18 cm Δ t = Δ D 1 + Δ D 2 2 = 0.01 + 0.01 2 = 0.01 cm ⇒ t = ( 0 .18 ± 0 .01 ) cm

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