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The internal resistance of a $2.1 \mathrm{~V}$ cell which gives a current of $0.2 \mathrm{~A}$ through a resistance of $10 \Omega$ is
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The correct answer is:
$0.5 \Omega$
\(\begin{aligned} & I=\frac{E}{R+r} \\ & 0.2 \times(10+r)=2.1 \\ & 10+r=\frac{2.1}{2} \times 10 \\ & r=10.5-10=0.5 \Omega\end{aligned}\)
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