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The inverse of the proposition $(p \wedge-q) \Rightarrow r$ is
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Verified Answer
The correct answer is:
$\sim p \vee q \Rightarrow \sim r$
Inverse of $p \Rightarrow q$ is $\sim p \Rightarrow \sim q$
$\therefore$ Inverse of $(p \wedge \sim q) \Rightarrow \mathrm{r}$ is
$$
\sim(p \wedge \sim q) \Rightarrow \sim r
$$
i.e., $\quad(\sim p \vee q) \Rightarrow \wedge \sim r$
$\therefore$ Inverse of $(p \wedge \sim q) \Rightarrow \mathrm{r}$ is
$$
\sim(p \wedge \sim q) \Rightarrow \sim r
$$
i.e., $\quad(\sim p \vee q) \Rightarrow \wedge \sim r$
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