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The ionic conductance of $\mathrm{Ba}^{2+}$ and $\mathrm{Cl}^{-}$ respectively are 127 and $76 \Omega^{-1} \mathrm{~cm}^{2}$ at infinite dilution. The equivalent conductance of $\mathrm{BaCl}_{2}$, at infinite dilution will be
ChemistryElectrochemistryBITSATBITSAT 2012
Options:
  • A $330 \Omega^{-1} \mathrm{~cm}^{2}$
  • B $203 \Omega^{-1} \mathrm{~cm}^{2}$
  • C $139 \Omega^{-1} \mathrm{~cm}^{2}$
  • D $51 \Omega^{-1} \mathrm{~cm}^{2}$
Solution:
1734 Upvotes Verified Answer
The correct answer is: $139 \Omega^{-1} \mathrm{~cm}^{2}$
$\begin{aligned} & \lambda_{\mathrm{m}}^{\circ} \text { for } \mathrm{BaCl}_{2}=\lambda_{\mathrm{m}}^{\circ} \mathrm{Ba}^{2+}+\lambda_{\mathrm{m}}^{\circ} \mathrm{Cl}^{-} \\ &=\frac{1}{2} \times 127+76=139.5 \Omega^{-1} \mathrm{~cm}^{2} \end{aligned}$

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