The ionization energy of H e + is 19.6 × 1 0 - 18 J a t o m - 1 . The energy of the first stationary state of L i + 2 will be

Question

The ionization energy of H e + is 19.6 × 1 0 - 18 J a t o m - 1 . The energy of the first stationary state of L i + 2 will be, 21.2 × 10 - 18 J / a t o m, 44.10 × 10 - 18 J / a t o m, 63.2 × 10 - 18 J / a t o m, 84.2 × 10 - 18 J / a t o m

MARKS App · Accepted Answer

E 1 for L i + 2 = E 1 for H × Z 2 L i E 1 for H e + = E 1 for H × Z 2 H e Thus, E 1 for L i + 2 = 9 4 × E 1 for H e + = 9 4 × 19.6 × 1 0 - 18 = 44.10 × 1 0 - 18 J / a t o m

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